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Java Get Working Directory Path


Note that an application can create p without any default Properties object, like this: Properties p = new Properties(); Also note that the value of system properties can be overwritten! Why would a decision making machine decide to destroy itself? Could you elaborate please? –C graphics Oct 31 '12 at 23:09 For some information about accessing a file on the class path, see stackoverflow.com/questions/1464291/… –downeyt Jan 17 at 12:47 Constructing paths in a relative way, by not using a leading separator to indicate you are constructing an absolute path, will use this relative path as the starting point. his comment is here

I bundle my java app into a Mac OS X app using appbundler and I could not figure out how to access the data inside my app using java code. Writing System Properties To modify the existing set of system properties, use System.setProperties. Oct 16 at 8:56 What is the potential advantage of using .normalize() in this context? –Ole V.V. I hope you understand my point. http://stackoverflow.com/questions/4871051/getting-the-current-working-directory-in-java

Java Get Project Directory

That is, changing the system properties within an application will not affect future invocations of the Java interpreter for this or any other application. At the time it is defined, a Path is provided with a series of one or more names. Invoking getRoot and // getParent on the "fullPath" // instance returns expected values.

This works fine in JAR files as well. Documentation The Java™ Tutorials Download Ebooks Download JDK Search Java Tutorials Hide TOC Basic I/O I/O Streams Byte Streams Character Streams Buffered Streams Scanning and Formatting Scanning Formatting I/O from the Not the current working directory in which the application is running. –Peter De Winter May 15 '13 at 14:22 1 I checked the first one—works perfectly :) –Erik Allik Sep Java Get Class Directory This is not a valid system property, so instead of returning null, this method returns the default value provided as a second argument: "Buy StayPuft Marshmallows!" System.getProperty("subliminal.message", "Buy StayPuft Marshmallows!"); The

subpath(0,2) home/joe home\joe Returns the subsequence of the Path (not including a root element) as specified by the beginning and ending indexes. Java Set Working Directory Constructing paths in a relative way, by not using a leading separator to indicate you are constructing an absolute path, will use this relative path as the starting point. To navigate from home to bar, you first navigate one level down to sally and then one more level down to bar. http://stackoverflow.com/questions/3153337/get-current-working-directory-in-java matches the CWD exactly (even with Windows' case insensitivity), and d.

args) throws Exception { URL location = Test.class.getProtectionDomain().getCodeSource().getLocation(); System.out.println(location.getFile()); } } share|improve this answer edited Feb 1 at 16:26 community wiki 3 revs, 3 users 70%Bigoloo This is a How To Get Current Working Directory In Java In Linux How can I get my program to show that it's in C:\Users\Justian\Documents. The simpler of the two getProperty methods takes a single argument, a property key For example, to get the value of path.separator, use the following statement: System.getProperty("path.separator"); The getProperty method returns If you need to convert the path to a string that can be opened from a browser, you can use toUri.

Java Set Working Directory

You should also as a bonus look at using a good object oriented command line argument parser. internet If the Path contains any redundant elements, it returns a path with those elements removed. Java Get Project Directory The setProperties method changes the set of system properties for the current running application. Java Get Current Directory Of Jar To get the actual path to the application's main folder see my answer below. –Peter De Winter May 15 '13 at 14:31 The problem with the "user.dir" property is,

Suggestions? this content If the passed-in path is already absolute, it returns the same Path object. String workingDir = System.getProperty("user.dir"); Example package com.mkyong.io; public class App{ public static void main (String args[]) { String workingDir = System.getProperty("user.dir"); System.out.println("Current working directory : " + workingDir); } } Output How to load properties file in Java on XML format or How to parse XML files in Java using DOM parser and Why Java doesn't support multiple inheritance . Java Get Root Directory

Problems with the examples? My words were somewhat poorly chosen. public class Test { public static void main(String... http://analysedesgeeks.com/java-get/java-get-working-directory.html It is built on WordPress, hosted by Liquid Web, and the caches are served by CloudFlare CDN.

is a descendent of the CWD –Michael Scheper May 15 '13 at 2:43 1 @MichaelScheper: Ooouch 2 down votes for a minor mistake...that hurts dude. How To Get Folder Path In Java getNameCount 3 3 Returns the number of elements in the path. Both of the preceding examples normalize to /home/joe/foo.

I'm trying to get my JAR to compile, but that's a separate issue at the moment.

asked 6 years ago viewed 213163 times active 8 months ago Blog Stack Overflow Podcast #97 - Where did you get that hat?! This object contains a complete set of system property definitions. see more linked questions… Related 115Changing the current working directory in Java?704Get current stack trace in Java1How to get the present working directory on Linux in Java 0Setting the working directory Java Working Directory Command Line the OS is Windows (Use File.separator instead, or a multi-argument File constructor); 3.

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Your code is broken, unless all these are true: 1. Maybe I can go just 3 folders back (i.e "Documents\Project\Dump\[file/folder]") –Justian Meyer Jun 30 '10 at 21:32 I would say what you want to do is get a handle The following code snippet iterates over a path, printing each name element: Path path = ...; for (Path name: path) { System.out.println(name); } The Path class also implements the Comparable interface. You can meet this using the relativize method.

Note that File.getCanonicalPath() throws a checked IOException but it will remove things like ../../../ share|improve this answer answered Jun 5 '12 at 14:57 cyber-monk 3,72751936 2 @cyber-monk..Awesome help man :) Could it be done by using the class path instead? Path fullPath = inputPath.toAbsolutePath(); } } The toAbsolutePath method converts the user input and returns a Path that returns useful values when queried. share|improve this answer answered Jun 30 '10 at 21:03 Michael Borgwardt 249k52370606 I want to dump a bunch of CSV files in a folder, have the program recognize all

share|improve this answer edited Jun 5 '13 at 15:20 answered Sep 27 '12 at 10:09 JSS 1,466920 6 It would be disservice not to downvote this answer. Path p3_to_p1 = p3.relativize(p1); In this example, the two paths share the same node, home. might result in a Path that no longer locates the intended file. Just use exactly that one as returned by getLocation() method.

If the property does not exist, this version of getProperty returns null. If the Ch’in dynasty was so short-lived, why was China named for it? For example: try { Path fp = path.toRealPath(); } catch (NoSuchFileException x) { System.err.format("%s: no such" + " file or directory%n", path); // Logic for case when file doesn't exist. } getRoot / C:\ Returns the root of the path.

This article is in continuation of my earlier post on Java e.g. Both retrieve the value of the property named in the argument list. content contest Term describing a zone subject to speeding Find the sum of all numbers below n that are a multiple of some set of numbers more hot questions question feed in the same directory).

Its easy just remember name of system property "user.dir" which gives directory from where java command has been executed. share|improve this answer edited May 10 at 20:39 vaxquis 5,97652846 answered Apr 11 '13 at 17:10 geoO 2,225165 2 The first one haven' t checked, but the second one will