Home > Java Get > Java Get Generic Class At Runtime

Java Get Generic Class At Runtime

Contents

Admittedly, there are in general easier ways to perform such a query. He is interested in finding concise means of expression in Java without sacrificing type safety. As a result, the Java compiler is able to store the information about the generic argument's type String of superclass MyGenericClass in the byte code of its subclass MyStringSubClass. Could you please explain how you get Foo out of this? http://analysedesgeeks.com/java-get/java-get-runtime-class-of-generic-type.html

The type arguments for statically declared types can be discovered at runtime. Here however, we examine an instance of a (non-static) inner class of a generic class's subtype. Thanks!ReplyLeave a Reply Cancel replyYour email address will not be published. posted 5 years ago shwetank singh, Your post was moved to a new topic. http://stackoverflow.com/questions/3403909/get-generic-type-of-class-at-runtime

Java Parameterizedtype

SCJP 1.5 shwetank singh Greenhorn Posts: 26 posted 6 years ago Thanks Jesper..and Jim..for wonderful insight! To show why, think of the following class hierarchy:class MyGenericClass { } class MyGenericSubClass extends MyGenericClass class MyStringSubSubClass extends MyGenericSubClass { }If we now callfindSuperClassParameterType(new MyStringSubClass(), MyGenericClass.class, 0);an exception will be In other words, while a new ArrayList() is really just a new ArrayList() at runtime, if a class extends ArrayList, then the JVM knows that String is the actual type argument As stated in the javadoc: /** * ParameterizedType represents a parameterized type such as * Collection. * * A parameterized type is created the first time it is needed by a

I've always done this by just creating a constructor in the generic DAO which takes a class argument containing the required Class of the entity. getImplicitUpperBounds public staticType[]getImplicitUpperBounds(WildcardTypewildcardType) Returns an array containing the sole value of Object if WildcardType.getUpperBounds() returns an empty array. Nov 14 '14 at 11:16 1 @Dominik Please see the updated example that you can copy and paste to test yourself. Java Cannot Select From Parameterized Type In other words, it CAN tell that in class A implements Comparable, the actual type parameter is String, but it CANNOT tell that in Set a = new TreeSet(), the actual

This can be achieved by adjusting our example code:public static Class findSubClassParameterType(Object instance, Class classOfInterest, int parameterIndex) { Map typeMap = new HashMap(); Class instanceClass = instance.getClass(); while (classOfInterest Java Type To Class I.e. Constructor Summary Constructors Constructor and Description TypeUtils() TypeUtils instances should NOT be constructed in standard programming. https://www.javacodegeeks.com/2013/12/advanced-java-generics-retreiving-generic-type-arguments.html Additionally, we have a hierarchy of abstract generic DAOs, so there's the problem of getting information on the actual parameter types for the most basic DAOs.

If we want to resolve this hierarchy, we have to resolve all of these dependencies. Java Gettypeparameters Method ReflectionUtil#getFieldClass(Class, String) loops through Class#getDeclaredFields() comparing each java.lang.reflect.Field#getName() with the invoked name, when a match is found, Field#getType() is returned with the Class object needed which represents the type of This uses reflection to battle Java's runtime type erasure. It seems to me this gives only unparametrized Foo.

Java Type To Class

static ParameterizedType parameterizeWithOwner(Typeowner, Classraw, Type...typeArguments) For example the component type of boolean[] is boolean Returns: GenericArrayType Since: 3.2 equals public staticbooleanequals(Typet1, Typet2) Check equality of types. Java Parameterizedtype So far, we assumed that the type parameter T for MyGenericClass was stored in a direct subclass. Java Get Generic Class Name However, when you are writing APIs that are to be used by other developers, you often want them to be as slim and easy as possible. (This can go from writing

Reference: Advanced Java generics: retreiving generic type arguments from our JCG partner Rafael Winterhalter at the My daily Java blog. http://analysedesgeeks.com/java-get/java-get-generic-type-runtime.html August 2013 um 15:11 Antworten Schreibe einen Kommentar Antworten abbrechen Gib hier Deinen Kommentar ein ... for each nested class. extends Map

Earlier, I used to just instantiate this type in the constructor, like so: public GenericJpaDao(Class entityBeanType) { this.entityBeanType = entityBeanType; } public JpaPersonDao extends GenericJpaEntityDao implements PersonDao { public PersonDao() { static Type[] getImplicitUpperBounds(WildcardTypewildcardType) Returns an array containing the sole value of Object if WildcardType.getUpperBounds() returns an empty param) { return param.getClass().getComponentType(); } } share|improve this answer answered Mar 5 '14 at 12:19 HRgiger 1,8281328 1 Note: this does not work when T is a type variable. weblink Java Annotations Tutorial5.

share|improve this answer edited Mar 23 at 12:53 answered Nov 4 '13 at 19:55 Cody A. Getgenericsuperclass Therefore this time, the generic type was irretrievably erased during compilation. Method ReflectionUtil#getMethodReturnType(Class, String) loops through Class#getDeclaredMethods() comparing each java.lang.reflect.Method#getName() with the invoked name, when a match is found, Method#getReturnType() is returned with the Class object needed which represents the return type

extends Bar>.

This is a tribute to Java's backwards compatibility: all generic variations of a Java class share a single representation within a running Java application. no, do not subscribeyes, replies to my commentyes, all comments/replies instantlyhourly digestdaily digestweekly digest Or, you can subscribe without commenting. But how to do that? Java Reflect Type getRawType public staticClassgetRawType(Typetype, TypeassigningType) Get the raw type of a Java type, given its context.

Why would the 'Church' be granted the exclusive right of producing alcohol? extends Foo> fooList = new ArrayList(); public static void main(String[] args) throws Exception { Field field = GenericTypeInfo.class.getDeclaredField("fooList"); Type type = field.getGenericType(); System.out.println("type: " + type); if (type instanceof ParameterizedType) { Really interesting!In the first version of the findSuperClassParameterType implementation the while condition looks a little incorrect: subClass != subClass.getSuperclass().Reply Rafael Winterhalter December 29th, 2013 at 12:11 amThank you for your feedback. check over here I tried creating a "generic helper" to let me create a subclass and get around the block...

However, in general, several problems can occur: For a class extending AbstractUserType, the result of the call to getActualTypeArguments()[0] will be a GenericArrayType, even though one might expect it to be Now, code runs fine, but Type is still 'T'. Holiday present-ation vs. Parameters: type - to resolve assigningType - type to be resolved against Returns: the resolved Class object or null if the type could not be resolved isArrayType public staticbooleanisArrayType(Typetype) Learn whether

static Type[] normalizeUpperBounds(Type[]bounds) This method strips out the redundant upper bound types in type variable types and Java would need reified generics for that to work. –Henning Aug 4 '10 at 8:51 add a comment| up vote 7 down vote This is my solution: import java.lang.reflect.Type; import java.lang.reflect.TypeVariable; For instance, Box is translated [at compile time] to type Box, which is called the raw type -- a raw type is a generic class or interface name without any type Parameters: owner - the owning type raw - the raw class to create a parameterized type instance for typeArgMappings - the mapping used for parameterization Returns: ParameterizedType Since: 3.2 wildcardType public

However, there's a better way, which I'll show in this post. In this particular case, the solution is simpler: abstract class Foo { abstract Class getTClass(); //... } and later on the derived class: class Bar extends Foo { @Override Class getTClass() Returns: whether or not the types can be assigned to their respective type variables. extends T> childClass) { Map resolvedTypes = new HashMap(); Type type = childClass; // start walking up the inheritance hierarchy until we hit baseClass while (!getClass(type).equals(baseClass)) { if (type

Does anyone know another solution or I did something wrong? Ok, no idea … but maybe I can now ask the reflection API … Getting the field is easy Field field = this.getClass().getField("type"); but with the field I cant do any String s = stack.pop(); System.out.printf( "s = '%s'\n", s ); } } share|improve this answer edited Mar 4 '15 at 2:19 Dave Jarvis 17k26107210 answered Apr 16 '11 at 5:51 bert But in your example, you're instantiating an abstract class.

Find the sum of all numbers below n that are a multiple of some set of numbers Using the /tmp folder for backups, recommended? The exact same piece of code has been part of the caveat emptor sample applicatication for the Java Persistence with Hibernate for quite some time.