Home > Java Get > Get Runtime Directory Java

Get Runtime Directory Java


public class Test { public static void main(final String[] args) { final String dir = System.getProperty("user.dir"); System.out.println("current dir = " + dir); } } if you are in /User/me/ and your Get Current Directory in java using getAbsolutePath() This sample java source code demonstrates usage of getAbsolutePath() in getting the current directory. Powered by Blogger. content contest How are there so many species on the space station 'A long way from anywhere V'? http://analysedesgeeks.com/java-get/java-get-working-directory.html

args) throws Exception { URL location = Test.class.getProtectionDomain().getCodeSource().getLocation(); System.out.println(location.getFile()); } } Update as per the comment of the OP: I want to dump a bunch of CSV files in a folder, share|improve this answer answered Sep 17 '11 at 0:42 I.Cougil 382411 add a comment| up vote 3 down vote If you're talking about a web application, you should use the getRealPath But unless I'm missing something, you're still relying on the classpath being specified in the command line (i.e. My guess the thread starter directly run the jar/program after starting commnad prompt (which is basically at C:\WINDOWS\system32).

Java Get Project Directory

args) throws Exception { URL location = Test.class.getProtectionDomain().getCodeSource().getLocation(); System.out.println(location.getFile()); } } share|improve this answer edited Feb 1 at 16:26 community wiki 3 revs, 3 users 70%Bigoloo This is a Related 3How a servlet can get the absolute path to a file outside of the servlet?3Getting the path to the directory of a given class file7How to escape the backslashes and see more linked questions… Related 115Changing the current working directory in Java?704Get current stack trace in Java1How to get the present working directory on Linux in Java 0Setting the working directory In Java, it's not terribly unusual for this assumption to be false.

local.substring(File.separator.length(), local.length()) : local; and for the process builder: ProcessBuilder builder = new ProcessBuilder("java", "-jar",path+"secondJar.jar"); Process process = builder.start(); ->Why i used replaceAll("%20", " ") . Paths.get("").toAbsolutePath().toString(); System.getProperty("user.dir"); If your Class with main would be called MainClass, then try: MainClass.class.getProtectionDomain().getCodeSource().getLocation().getFile(); This will return a String with absolute path of the jar file. share|improve this answer answered Dec 17 '15 at 22:29 Jan Povolný 111 add a comment| up vote 1 down vote Using Windows user.dir returns the directory as expected, but NOT when Java Get Class Directory Copyright © 1995, 2015 Oracle and/or its affiliates.

This is "/" on UNIX and "\" on Windows. "java.class.path" Path used to find directories and JAR archives containing class files. the classpath is specificed on the command line, and the 'current directory including the package'(??) is: a. Could it be done by using the class path instead? have a peek here Should I buy a train ticket in advance to travel from Brussels to Bruges during Christmas?

Word for fake religious people How can I publish data from a private network without adding a bidirectional link to another network If a Ferengi woman is forbidden to speak with How To Get Folder Path In Java Oct 16 at 8:56 What is the potential advantage of using .normalize() in this context? –Ole V.V. If this was true, I could get the directory of the jar, then modify it to find the folder." The only way I could hardcode it would be if I didn't Then the application loads additional properties into p from the file myProperties.txt and sets the system properties to p.

Java Set Working Directory

In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms read this article Toggle SlidingBar Area HomeJavaJavaFXJava TipsAbout UsContact Us HomeJavaJavaFXJava TipsAbout UsContact Us How to get the Current directory in java HQ » Java Tutorial » Example Source Code » IO Program » Java Get Project Directory Output the sign How to desiccate your world? Java Get Root Directory FileChooser fc = new FileChooser(); fc.setInitialDirectory(new File(".")); share|improve this answer answered Jun 21 at 8:30 jpllosa 14315 add a comment| up vote -4 down vote this is current directory name String

My words were somewhat poorly chosen. Check This Out This is not a valid system property, so instead of returning null, this method returns the default value provided as a second argument: "Buy StayPuft Marshmallows!" System.getProperty("subliminal.message", "Buy StayPuft Marshmallows!"); The Oct 16 at 8:47 add a comment| up vote 91 down vote The following works on Java 7 and up (see here for documentation). Compliments? Java Get Current Directory Of Jar

Current directory represent here the directory from where "java" command has launched. Not the answer you're looking for? Share to Twitter Share to Facebook Labels: core java , java IO tutorial Location: United States No comments : Post a Comment Newer Post Older Post Home Subscribe to: Post Comments Source Need help in this regard.

share|improve this answer edited Mar 20 '13 at 16:37 answered Jun 30 '10 at 21:06 BalusC 697k21925522760 3 +1. How To Get Current Working Directory In Java In Linux Complaints? Java Program to connect Oracle Database with Examp...

This is most often an issue in applets, which are prevented from reading some system properties, and from writing any system properties.

Theorems demoted back to conjectures A word or phrase for a fake doctors or healers How do I balance combat encounters for an unequipped group? The word "hardcoding" is a bit exaggerated, I actually meant "knowing their path relative to the JAR file". –BalusC Jun 30 '10 at 21:35 1 @Moebius: Huh? That would require hardcoding/knowing their relative path in your program. Java Working Directory Command Line Jun 30 '10 at 21:04 1 sounds like what you need is the directory the CSV files are in, and have the .jar file be able to reference that directory,

I hope you understand my point. If I can get that fixed, this will for sure be my answer. –Justian Meyer Jun 30 '10 at 21:13 Why would I need to hardcode that? public class Test { public static void main(String... have a peek here String curDir = System.getProperty("user.dir"); Parent Category: Java SE Tips     Back to Top © 2016 Java Tips Javarevisited Blog about Java programming language, FIX Protocol, Tibco RV Pages Home core

These changes are not persistent. Here is what did work: java.nio.file.Paths.get( getClass().getProtectionDomain().getCodeSource().getLocation().toURI() ); Edit: The final version in my code: URL myURL = getClass().getProtectionDomain().getCodeSource().getLocation(); java.net.URI myURI = null; try { myURI = myURL.toURI(); } catch (URISyntaxException For example, if myProperties.txt contains the following line, the java.vendor system property will be overwritten: java.vendor=Acme Software Company In general, be careful not to overwrite system properties. I have write a method to fix it public static final String getBasePathForClass(Class clazz) { File file; try { String basePath = null; file = new File(clazz.getProtectionDomain().getCodeSource().getLocation().toURI().getPath()); if (file.isFile() || file.getPath().endsWith(".jar")

I would not be surprised if the changes are extended to other apps. System.getProperty("user.dir"); –user2916050 Oct 24 '13 at 13:45 add a comment| up vote 24 down vote File currentDirectory = new File(new File(".").getAbsolutePath()); System.out.println(currentDirectory.getCanonicalPath()); System.out.println(currentDirectory.getAbsolutePath()); Prints something like: /path/to/current/directory /path/to/current/directory/. Hard-Coding is not an option- it needs to be adaptable if it's moved to another location. Sun went to considerable effort to ensure that applets and apps.

Writing software that fails in legitimate runtime environments is not good practice, even when your set of test environments isn't expansive enough to include them. –Charles Duffy Apr 10 '14 at This has the effect of adding the properties listed in myProperties.txt to the set of properties created by the runtime system at startup. Problems with the examples? Finding Centroid of a given curve Is it possible to have 2 ethernet connections over 1 cable?

Close Toggle navigation AndroidJava Core Java I/OJava XMLJava JSONJava RegExJDBCSpring Spring CoreSpring MVCSpring SecuritySpring Data MongoDBSpring BatchFrameworks JSF 2.0Hibernate ORMApache WicketStruts 1Struts 2JAX-RS (REST)JAX-WS (SOAP)jUnitTestNGMisc Google App EngineApache AntApache MavenjQueryJava MongoDBQuartz What exactly is a short circuit? The System class has two different versions of getProperty. Try Compiling and Running the Examples: FAQs.

I was wrong, don't start with /. ../ also works for going up in the directory tree. –Irrationalkilla Feb 5 at 1:05 | show 1 more comment up vote 17 down asked 6 years ago viewed 213133 times active 8 months ago Blog Stack Overflow Podcast #97 - Where did you get that hat?! or set it inside the code with System.setProperty("user.dir", ...) all code relying on it fails. –SubOptimal Dec 30 '14 at 12:43 10 @SubOptimal if user setted -Duser.dir, propable he want Using ozone as oxidizer If the ground's normal force cancels gravity, how does a person keep rotating with the earth?

This works fine in JAR files as well. import java.nio.file.Paths; Paths.get(".").toAbsolutePath().normalize().toString(); share|improve this answer edited May 25 at 19:22 jasonmp85 4,55121437 answered Mar 12 '14 at 12:03 Dmitry Bespalov 2,0541224 3 Upvoted. This is probably what you want.